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from sys import argv, stdout as cout
from time import sleep as sl
print("Rewinding.......",end = '') # If end is given output isn't flushed. But why?
cout.flush()
for i in range(0,20):
sl(0.2)
print(".",end='',flush = True) #No output is printed if flush wasn't specified as true.
print("Done") #Output is by default flushed here
When I specified end and sleep, I noticed that output wasn't flushed until next print where it was by default flushed.
Why does this happen? I had to manually flush the output.
989
The end parameter in the print function is used to add any string. At the end of the output of the print statement in python. By default, the print function ends with a newline. Passing the whitespace to the end parameter (end=' ') indicates that the end character has to be identified by whitespace and not a newline.
A Flush Cut refers to lamination that is trimmed even with the edge of the printed piece. A Flush Cut offers aesthetic benefits, but the edge of the printing is not completely enclosed in film. Therefore, it does not completely protect the edge of the paper from moisture, oil or grime like the Sealed Edge method.
flush=True will force our terminal to print it.
In fact this is the default behavior of the underlying stdio functions.
When the output is to console, the stream will be automatically flushed when a newline is encountered, but not other characters.
If the output is not a console, then even newline won't trigger a flush.
If you want to make sure about flush, you can tell the print() explicitly:
print("Rewinding.......",end = '',flush=True)
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