Why doesn't [[]] == list(list()) [duplicate]

Question

I just randomly observed the following in Python and am curious to know the reason why this evaluates to False:

list(list()) == [[]]

Interestingly if you rearrange the syntax in the following ways, the first way evaluates as False, but the second as True:

list([]) == [[]]
[list()] == [[]]

What is going on under the hood here?

Answer 1

list does not construct a list that contains its argument; it constructs a list whose elements are contained in its argument. list([]) does not return [[]]; it returns []. Thus, list(list()) == list([]) == [].