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I've been studying operator precedence and it was explained to me that x =! 5 returns false. I can't seem to explain why to myself again. I know =! isn't a operator so then x and 5 remain. So does that mean Ruby doesn't know what to do? If so ruby should return an error because x can have no value? Does Ruby stop at the operator and then assign a value of false to x?
x =! 5
=> false
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The true operator returns the bool value true to indicate that its operand is definitely true. The false operator returns the bool value true to indicate that its operand is definitely false.
The equal-to operator ( == ) returns true if both operands have the same value; otherwise, it returns false . The not-equal-to operator ( != ) returns true if the operands don't have the same value; otherwise, it returns false .
x == y compares x and y . The result of x == y will be true if x and y are equal, false otherwise.
Equal to - True if both operands are equal. x == y. != Not equal to - True if operands are not equal. x != y.
This is because x =! 5 is being interpreted as x = (!5) (! has higer precedence than =). In Ruby every object is true except nil and false. 5 has truthy value which you are negating using the operator !. So false as result is being assigned to the local variable x.
! Called Logical NOT Operator - is used to reverse the logical state of its operand. If a condition is true, then Logical NOT operator will make false.
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