I have this naive regex "<([\s]|[^<])+?>" (excluding the quotation marks). It seems so straightforward but it is indeed evil when it works against the below HTML text. It sends the Java regular expression engine to an infinite loop.
I have another regex ("<.+?>"), which does somewhat the same thing, but it doesn't kill anything. Do you know why this happens?
<script language="JavaScript" type="text/javascript">
var numDivs, layerName;
layerName = "lnavLayer";
catLinkName = "category";
numDivs = 2;
function toggleLayer(layerID){
if (!(navigator.appName == "Netscape" && navigator.appVersion.substr(0, 1) < 5)){
thisLayer = document.getElementById(layerName + layerID);
categoryLink = document.getElementById(catLinkName + layerID);
closeThem();
if (thisLayer.className == 'subnavDefault'){
thisLayer.className = 'subnavToggled';
categoryLink.className = 'leftnavLinkSelectedSection';
}
}
}
function closeThem(){
for(x = 0; x < numDivs; x++){
theLayer = document.getElementById(layerName + (x
+ 1));
thecategoryLink = document.getElementById(catLinkName + (x + 1));
theLayer.className = 'subnavDefault';
thecategoryLink.className = 'leftnavLink';
}
} var flag = 0; var lastClicked = 0
//-->
</script>
it even keeps looping with an online Java regex tool (such as www.fileformat.info/tool/regex.htm) or a utility like RegexBuddy.
Java Regex API provides 1 interface and 3 classes in java. util. regex package.
Regular expressions can be used to perform all types of text search and text replace operations. Java does not have a built-in Regular Expression class, but we can import the java. util. regex package to work with regular expressions.
Regex is faster for large string than an if (perhaps in a for loops) to check if anything matches your requirement.
There is no reason in the world to avoid throwing a regex at a string like "<a href='foo'>stuff</a>" . Modern regexes have no trouble with this.
The reason the Java regex engine crashes is that this part of your regex causes a stack overflow (indeed!):
[\s]|[^<]
What happens here is that every character matched by \s can also be matched by [^<]. That means there are two ways to match each whitespace character. If we represent the two character classes with A and B:
A|B
Then a string of three spaces could be matched as AAA, AAB, ABA, ABB, BAA, BAB, BBA, or BBB. In other words the complexity of this part of the regex is 2^N. This will kill any regex engine that doesn't have any safeguards against what I call catastrophic backtracking.
When using alternation (vertical bar) in a regex, always make sure the alternatives are mutually exclusive. That is, at most one of the alternatives may be allowed to match any given bit of text.
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