Why does the html input with type "number" allow the letter 'e' to be entered in the field?

Question

Because that's exactly how the spec says it should work. The number input can accept floating-point numbers, including negative symbols and the e or E character (where the exponent is the number after the e or E):

A floating-point number consists of the following parts, in exactly the following order:

1. Optionally, the first character may be a "-" character.
2. One or more characters in the range "0—9".
3. Optionally, the following parts, in exactly the following order:
   1. a "." character
   2. one or more characters in the range "0—9"
4. Optionally, the following parts, in exactly the following order:
   1. a "e" character or "E" character
   2. optionally, a "-" character or "+" character
   3. One or more characters in the range "0—9".

We can make it So simple like below

<input type="number"  onkeydown="javascript: return event.keyCode == 69 ? false : true" />

Updated Answer

we can make it even more simple as @88 MPG suggests

<input type="number" onkeydown="return event.keyCode !== 69" />

The best way to force the use of a number composed of digits only:

<input type="number" onkeydown="javascript: return event.keyCode === 8 ||
event.keyCode === 46 ? true : !isNaN(Number(event.key))" />

this avoids 'e', '-', '+', '.' ... all characters that are not numbers !

To allow number keys only:

isNaN(Number(event.key))

but accept "Backspace" (keyCode: 8) and "Delete" (keyCode: 46) ...

HTML input number type allows "e/E" because "e" stands for exponential which is a numeric symbol.

Example 200000 can also be written as 2e5. I hope this helps thank you for the question.　　　　　　　　　　

<input type="number" onkeydown="return FilterInput(event)" onpaste="handlePaste(event)"  >

function FilterInput(event) {
    var keyCode = ('which' in event) ? event.which : event.keyCode;

    isNotWanted = (keyCode == 69 || keyCode == 101);
    return !isNotWanted;
};
function handlePaste (e) {
    var clipboardData, pastedData;

    // Get pasted data via clipboard API
    clipboardData = e.clipboardData || window.clipboardData;
    pastedData = clipboardData.getData('Text').toUpperCase();

    if(pastedData.indexOf('E')>-1) {
        //alert('found an E');
        e.stopPropagation();
        e.preventDefault();
    }
};

A simple solution to exclude everything but integer numbers

<input  
    type="number"
    min="1" 
    step="1"
    onkeypress="return event.keyCode === 8 || event.charCode >= 48 && event.charCode <= 57">

This solution does not prevent copy and pasting (including the letter 'e').

To hide both letter e and minus sign - just go for:

onkeydown="return event.keyCode !== 69 && event.keyCode !== 189"