<pre class="prettyprint"><code>printf("%f", 1.0); //prints 1.0 </code></pre> but <pre class="prettyprint"><code>printf("%f", 1); // prints 0.0 </code></pre> How did the conversion happen?

<code>printf("%f", 1);</code> causes undefined behavior, because <code>double</code> is expected, but you passed an <code>int</code>. There is no explanation of why it prints <code>0.0</code>, because the behavior is undefined.

Why does printf print an integer as a double? [duplicate]

Tags:

c

printf

printf("%f", 1.0); //prints 1.0

but

printf("%f", 1);  // prints 0.0

How did the conversion happen?

313

asked Dec 23 '22 18:12

redkont

1 Answers

printf("%f", 1); causes undefined behavior, because double is expected, but you passed an int. There is no explanation of why it prints 0.0, because the behavior is undefined.