Consider the following program (see live demo here).
#include <stdio.h> int main(void) { int ; // Missing variable name puts("Surprise"); }
My compiler, gcc 4.8.1, gives the below warning:
[Warning] useless type name in empty declaration [enabled by default]
Why does it compile fine? Shouldn't I get a compiler error? g++ 4.8.1 gives the following error when I compile it as a C++ program:
[Error] declaration does not declare anything [-fpermissive]
The C standard says
A declaration other than a static_assert declaration shall declare at least a declarator (other than the parameters of a function or the members of a structure or union), a tag, or the members of an enumeration.
C++ says
In a simple-declaration, the optional init-declarator-list can be omitted only when declaring a class (Clause 9) or enumeration.
A violation of this in either language requires a diagnostic. The standards do not talk about compiler errors or warnings. A warning is a diagnostic.
Your code is illegal (i.e. erroneous, ill-formed, constraint-violating) in both C and C++. The reason you get a "warning" in one language and "error" in another is just a quirk of your compiler and your compiler setup. After all, neither language really formally differentiates between "warnings" and "errors". GCC under its default settings just happens to be more permissive in C mode (mostly for historical reasons).
Use -pedantic-errors
in GCC, and you will get an "error" in C code as well. (Note that -pedantic-errors
does not simply blindly turn all "warnings" into "errors". It attempts to report only actual constraint violations as "errors".)
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