When class is inherited from nothing, I have an object of instance type.
>>> class A(): pass;
>>> a = A()
>>> type(a)
<type 'instance'>
>>> type(a) is A
False
>>> type(A)
<type 'classobj'>
However, when I have the same class inheriting from an object, the created object is type of A.
>>> class A(object): pass;
>>> a = A()
>>> type(a)
<class '__main__.A'>
>>> type(a) is A
True
>>> type(A)
<type 'type'>
What is the logic behind this? Does this mean every class should inherit from object?
In Python 3, those two are the same. In Python 2, however:
class A: pass # old-style class
class B(object): pass # new-style class
From New-style and classic classes in the documentation:
Up to Python 2.1, old-style classes were the only flavour available to the user. The concept of (old-style) class is unrelated to the concept of type: if
x
is an instance of an old-style class, thenx.__class__
designates the class ofx
, buttype(x)
is always<type 'instance'>
. This reflects the fact that all old-style instances, independently of their class, are implemented with a single built-in type, called instance.New-style classes were introduced in Python 2.2 to unify classes and types. A new-style class is neither more nor less than a user-defined type. If
x
is an instance of a new-style class, thentype(x)
is the same asx.__class__
.The major motivation for introducing new-style classes is to provide a unified object model with a full meta-model. It also has a number of immediate benefits, like the ability to subclass most built-in types, or the introduction of "descriptors", which enable computed properties.
For these reasons, it's a good idea to use new-style classes whenever you can. The only reason old-style classes even exist in Python 2.2+ is for backwards compatibility; in Python 3, old-style classes were removed.
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