Go doesn't seem to enforce the struct adhering to the interface. Why does the following code compile?
package main
type LocalInterface interface {
SomeMethod(string) error
SomeOtherMethod(string) error
}
type LocalStruct struct {
LocalInterface
myOwnField string
}
func main() {
var localInterface LocalInterface = &LocalStruct{myOwnField:"test"}
localInterface.SomeMethod("calling some method")
}
It seems like this should not compile since SomeMethod
is not implemented.go build
results in no issues.
Running it results in the runtime error:
> go run main.go
panic: runtime error: invalid memory address or nil pointer dereference
[signal 0xc0000005 code=0x0 addr=0x20 pc=0x4013b0]
goroutine 1 [running]:
panic(0x460760, 0xc08200a090)
C:/Go/src/runtime/panic.go:464 +0x3f4
main.(*LocalStruct).SomeMethod(0xc0820064e0, 0x47bf30, 0x13, 0x0, 0x0)
<autogenerated>:3 +0x70
main.main()
C:/Users/kdeenanauth/Documents/git/go/src/gitlab.com/kdeenanauth/structTest/main.go:16 +0x98
exit status 2
When a type is embedded (in your example LocalInterface
is embedded inside LocalStruct
), Go creates a field of the embedded type and promotes its methods to the enclosing type.
So the following declaration
type LocalStruct struct {
LocalInterface
myOwnField string
}
is equivalent to
type LocalStruct struct {
LocalInterface LocalInterface
myOwnField string
}
func (ls *LocalStruct) SomeMethod(s string) error {
return ls.LocalInterface.SomeMethod(s)
}
Your program panics with nil pointer dereference because LocalInterface
field is nil
.
The following program "fixes" the panic (http://play.golang.org/p/Oc3Mfn6LaL):
package main
type LocalInterface interface {
SomeMethod(string) error
}
type LocalStruct struct {
LocalInterface
myOwnField string
}
type A int
func (a A) SomeMethod(s string) error {
println(s)
return nil
}
func main() {
var localInterface LocalInterface = &LocalStruct{
LocalInterface: A(10),
myOwnField: "test",
}
localInterface.SomeMethod("calling some method")
}
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