Why does GCC produce stack preservation instructions when they're not necessary?

Question

I'm compiling the following simple demonstration function:

int add(int a, int b) {
    return a + b;
}

Naturally this function would be inlined, but let's assume that it's dynamically linked or not inlined for some other reason. With optimization disabled, the compiler produces the expected code:

00000000 <add>:
   0:   55                      push   ebp
   1:   89 e5                   mov    ebp,esp
   3:   8b 45 0c                mov    eax,DWORD PTR [ebp+0xc]
   6:   03 45 08                add    eax,DWORD PTR [ebp+0x8]
   9:   5d                      pop    ebp
   a:   c3                      ret

Since there are no function calls inside this function, the instructions at 0, 1 and 9 seemingly have no purpose. Since optimization is disabled, this is acceptable.

However, when compiling while optimizing for size with -Os -s, the exact same code is produced. It seems rather wasteful to increase the size of the function by 66% with these options.

Why is the code not optimized to the following?

00000000 <add>:
   0:   8b 45 0c                mov    eax,DWORD PTR [esp+0x8]
   3:   03 45 08                add    eax,DWORD PTR [esp+0x4]
   6:   c3                      ret

Does the compiler just not consider this worth optimizing or is it related to other details like function alignment?

Answer 1

This is done to preserve the ability of the debugger to step through your code.

If you really want to disable this try -fomit-frame-pointer.

Compiling your above code using -Os -fomit-frame-pointer -S -masm=intel gave this:

    .file   "frame.c"
    .intel_syntax noprefix
    .text
    .globl  _add
    .def    _add;   .scl    2;  .type   32; .endef
_add:
    mov eax, DWORD PTR [esp+8]
    add eax, DWORD PTR [esp+4]
    ret
    .ident  "GCC: (rev0, Built by MinGW-builds project) 4.8.0"