Why does declaring a descriptor class in the __init__ function break the descriptor functionality?

Question

In class B below I wanted the __set__ function in class A to be called whenever you assign a value to B().a . Instead, setting a value to B().a overwrites B().a with the value. Class C assigning to C().a works correctly, but I wanted to have a separate instance of A for each user class, i.e. I don't want changing 'a' in one instance of C() to change 'a' in all other instances. I wrote a couple of tests to help illustrate the problem. Can you help me define a class that will pass both test1 and test2?

class A(object):
    def __set__(self, instance, value):
        print "__set__ called: ", value

class B(object):
    def __init__(self):
        self.a = A()

class C(object):
    a = A()

def test1( class_in ):
    o = class_in()
    o.a = "test"
    if isinstance(o.a, A):
        print "pass"
    else:
        print "fail"

def test2( class_in ):
    o1, o2 = class_in(), class_in()
    if o1.a is o2.a:
        print "fail"
    else:
        print "pass"

Answer 1

Accordingly to the documentation:

The following methods only apply when an instance of the class containing the method (a so-called descriptor class) appears in the class dictionary of another new-style class, known as the owner class. In the examples below, “the attribute” refers to the attribute whose name is the key of the property in the owner class’ __dict__. Descriptors can only be implemented as new-style classes themselves.

So you can't have descriptors on instances.

However, since the descriptor gets a ref to the instance being used to access it, just use that as a key to storing state and you can have different behavior depending on the instance.