Grouping.
As a particular example, consider that you can declare a variable of function type such as
int f(int);
Now, how would you declare a pointer to such a thing?
int *f(int);
Nope, doesn't work! This is interpreted as a function returning int*
. You need to add in the parentheses to make it parse the right way:
int (*f)(int);
The same deal with arrays:
int *x[5]; // array of five int*
int (*x)[5]; // pointer to array of five int
There's generally allowed to use parentheses in such declarations because the declaration, from the syntactical point of view looks always like this:
<front type> <specification>;
For example, in the following declaration:
int* p[2];
The "front type" is int
(not int*
) and the "specification" is * p[2]
.
The rule is that you can use any number of parentheses as needed in the "specification" part because they are sometimes inevitable to disambiguate. For example:
int* p[2]; // array of 2 pointers to int; same as int (*p[2]);
int (*p)[2]; // pointer to an array of 2 ints
The pointer to an array is a rare case, however the same situation you have with a pointer to function:
int (*func(int)); // declares a function returning int*
int (*func)(int); // declares a pointer to function returning int
This is the direct answer to your question. If your question is about the statement like C(y)
, then:
(C(y))
and you'll get what you wantedIf you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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