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Why does an IllegalThreadStateException occur when Thread.start is called again

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public class SieveGenerator{

static int N = 50;
public static void main(String args[]){

    int cores = Runtime.getRuntime().availableProcessors();

    int f[] = new int[N];

    //fill array with 0,1,2...f.length
    for(int j=0;j<f.length;j++){
        f[j]=j;
    }

    f[0]=0;f[1]=0;//eliminate these cases

    int p=2;

    removeNonPrime []t = new removeNonPrime[cores];

    for(int i = 0; i < cores; i++){
        t[i] = new removeNonPrime(f,p);
    }

    while(p <= (int)(Math.sqrt(N))){
        t[p%cores].start();//problem here because you cannot start a thread which has already started(IllegalThreadStateException)
        try{
            t[p%cores].join();
        }catch(Exception e){}
        //get the next prime
        p++;
        while(p<=(int)(Math.sqrt(N))&&f[p]==0)p++;
    }


    //count primes
    int total = 0;
    System.out.println();

    for(int j=0; j<f.length;j++){
        if(f[j]!=0){
            total++;
        }
    }
    System.out.printf("Number of primes up to %d = %d",f.length,total);
}
}


class removeNonPrime extends Thread{
int k;
int arr[];

public removeNonPrime(int arr[], int k){
    this.arr = arr;
    this.k = k;
}

public void run(){
    int j = k*k;
    while(j<arr.length){
        if(arr[j]%k == 0)arr[j]=0;
        j=j+arr[k];

    }
}
}

Hi I'm getting an IllegalThreadStateException when I run my code and I've figured it's because I am trying to start a thread that has already been started. So how could I kill or stop the thread each time, to get around this problem?

like image 286
user1014888 Avatar asked Nov 09 '11 22:11

user1014888


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What happens when thread start is called?

If you call start() method on Thread, Java Virtual Machine will call run() method and two threads will run concurrently now - Current Thread and Other Thread or Runnable implementation.

What happens when thread start is called in Java?

start. Causes this thread to begin execution; the Java Virtual Machine calls the run method of this thread. The result is that two threads are running concurrently: the current thread (which returns from the call to the start method) and the other thread (which executes its run method).

What is the use of IllegalThreadStateException?

Class IllegalThreadStateException Thrown to indicate that a thread is not in an appropriate state for the requested operation. See, for example, the suspend and resume methods in class Thread .

What happens when a thread finishes?

Finishing Threads So when does a thread finish? It happens in one of two cases: all instructions in the Runnable are executed. an uncaught exception is thrown from the run method.


2 Answers

how could I kill or stop the thread each time, to get around this problem?

The answer is, you can't. Once started, a Thread may not be restarted. This is clearly documented in the javadoc for Thread. Instead, what you really want to do is new an instance of RemoveNonPrime each time you come around in your loop.

You have a few other problems in your code. First, you need to increment p before using it again:

for(int i = 0; i < cores; i++){
    t[i] = new removeNonPrime(f,p); //<--- BUG, always using p=2 means only multiples of 2 are cleared
}

Second, you might be multithreaded, but you aren't concurrent. The code you have basically only allows one thread to run at a time:

while(p <= (int)(Math.sqrt(N))){
    t[p%cores].start();//
    try{
        t[p%cores].join(); //<--- BUG, only the thread which was just started can be running now
    }catch(Exception e){}
    //get the next prime
    p++;
    while(p<=(int)(Math.sqrt(N))&&f[p]==0)p++;
}

Just my $0.02, but what you are trying to do might work, but the logic for selecting the next smallest prime will not always pick a prime, for example if one of the other threads hasn't processed that part of the array yet.

Here is an approach using an ExecutorService, there are some blanks (...) that you will have to fill in:

/* A queue to trick the executor into blocking until a Thread is available when offer is called */
public class SpecialSyncQueue<E> extends SynchronousQueue<E> {
    @Override
    public boolean offer(E e) {
        try {
            put(e);
            return true;
        } catch (InterruptedException ex) {
            Thread.currentThread().interrupt();
            return false;
        }
    }
}

ExecutorService executor = new ThreadPoolExecutor(cores, cores, new SpecialSyncQueue(), ...);
void pruneNonPrimes() {
    //...
    while(p <= (int)(Math.sqrt(N))) {
        executor.execute(new RemoveNonPrime(f, p));
        //get the next prime
        p++;
        while(p<=(int)(Math.sqrt(N))&&f[p]==0)p++;
    }


    //count primes
    int total = 0;
    System.out.println();

    for(int j=0; j<f.length;j++){
        if(f[j]!=0){
            total++;
        }
    }
    System.out.printf("Number of primes up to %d = %d",f.length,total);
}



class RemoveNonPrime extends Runnable {
    int k;
    int arr[];

    public RemoveNonPrime(int arr[], int k){
        this.arr = arr;
        this.k = k;
    }

    public void run(){
        int j = k*k;
        while(j<arr.length){
            if(arr[j]%k == 0)arr[j]=0;
            j+=k;
        }
    }
}
like image 191
Tim Bender Avatar answered Oct 04 '22 20:10

Tim Bender


You could implement Runnable instead and use new Thread( $Runnable here ).start() or use a ExecutorService to reuse threads.

like image 26
MasterCassim Avatar answered Oct 04 '22 20:10

MasterCassim