map() creates a new array from calling a function for every array element. map() calls a function once for each element in an array. map() does not execute the function for empty elements. map() does not change the original array.
An array in JavaScript is also an object and variables only hold a reference to an object, not the object itself. Thus both variables have a reference to the same object.
map() method allows you to loop over every element in an array and modify or add to it and then return a different element to take that elements place. However . map() does not change the original array. It will always return a new array.
You're not modifying your original array. You're modifying the objects in the array. If you want to avoid mutating the objects in your array, you can use Object.assign
to create a new object with the original's properties plus any changes you need:
const freeProduct = function(products) {
return products.map(x => {
return Object.assign({}, x, {
productType: "free"
});
});
};
2018 Edit:
In most browsers you can now use the object spread syntax instead of Object.assign
to accomplish this:
const freeProduct = function(products) {
return products.map(x => {
return {
...x,
productType: "free"
};
});
};
To elaborate on SimpleJ's answer - if you were to === the two arrays, you would find that they would not be equal (not same address in memory) confirming that the mapped array is in fact a new array. The issue is that you're returning a new array, that is full of references to the SAME objects in the original array (it's not returning new object literals, it's returning references to the same object). So you need to be creating new objects that are copies of the old objects - ie, w/ the Object.assign example given by SimpleJ.
Unfortunately, whether the spread operator nor the object assign operator does a deep copy.... You need to use a lodash like function to get areal copy not just a reference copy.
const util = require('util');
const print = (...val) => {
console.log(util.inspect(val, false, null, false /* enable colors */));
};
const _ = require('lodash');
const obj1 = {foo:{bar:[{foo:3}]}};
const obj2 = {foo:{bar:[{foo:3}]}};
const array = [obj1, obj2];
const objAssignCopy = x => { return Object.assign({}, x, {})};
const spreadCopy = x => { return {...x}};
const _Copy = x => _.cloneDeep(x);
const map1 = array.map(objAssignCopy);
const map2 = array.map(spreadCopy);
const map3 = array.map(_Copy);
print('map1', map1);
print('map2', map2);
print('map3', map3);
obj2.foo.bar[0].foo = "foobar";
print('map1 after manipulation of obj2', map1); // value changed
print('map2 after manipulation of obj2', map2); // value changed
print('map3 after manipulation of obj2', map3); // value hasn't changed!
Array Iterator Array.map() creates the new array with the same number of elements or does not change the original array. There might be the problem with referencing if there is object inside the array as it copies the same reference, so, when you are making any changes on the property of the object it will change the original value of the element which holds the same reference.
The solution would be to copy the object, well, array.Splice()
and [...array]
(spread Operator) would not help in this case, you can use JavaScript Utility library like Loadash or just use below mention code:
const newList = JSON.parse(JSON.stringify(orinalArr))
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With