Why does a delegate with no parameters compile?

Question

I'm confused why this compiles:

    private delegate int MyDelegate(int p1, int p2);

    private void testDelegate()
    {
        MyDelegate imp = delegate 
        {
            return 1;
        };
    }

MyDelegate should be a pointer to a method that takes two int parameters and returns another int, right? Why am I allowed to assign a method that takes no parameters?

Interestingly, these doesn't compile (it complains about the signature mismatches, as I'd expect)

    private void testDelegate()
    {
        // Missing param
        MyDelegate imp = delegate(int p1)
        {
            return 1;
        };

        // Wrong return type
        MyDelegate imp2 = delegate(int p1, int p2)
        {
            return "String";
        };
    }

Thanks for any help!

Ryan

Answer 1

Your first example is short-hand syntax if the delegate doesn't need the parameters. If you need even one of them, you need to provide them all, which is why the first part of the second example won't compile.