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Why does 4 < '3' return True in Python 2?
Is it because when I place single quotes around a number Python sees it as a string and strings are bigger than numbers?
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By default, an object is considered true unless its class defines either a bool() method that returns False or a len() method that returns zero, when called with the object. Here are most of the built-in objects considered false: Constants defined to be false: None and False.
Because True is equal to 1 and False is equal to 0 , adding Booleans together is a quick way to count the number of True values.
This is because on the ASCII (American Standard Code For Information Interchange) CHART the letter "a" equates to 97 (in decimal values) while the letter "b" equates to 98 (in the decimal values).
7 is the correct answer to the given question. In the given question the 3 will be represented as 011 in bits format ans 4 is represented as 100 as the bits format .
Yes, any number will be less than any string (including the empty string) in Python 2.
In Python 3, you can't make arbitrary comparisons. You'll get a TypeError.
From the link in eryksun's comment:
if (PyNumber_Check(v)) vname = ""; else vname = v->ob_type->tp_name; if (PyNumber_Check(w)) wname = ""; else wname = w->ob_type->tp_name; c = strcmp(vname, wname); So at least in recent versions of CPython 2.x, type names are compared, with an empty string used instead of the type name for any numeric type.
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