I'm trying to learn more about this liberal language and a good explanation would be awesome.
Thanks!
In a way, yes it is 1.
Because == (and === ) test to see if two objects are the same object and not if they are identical objects.
Because they don't represent equally convertible types/values. The conversion used by == is much more complex than a simple toBoolean conversion used by if ('true') . So given this code true == 'true' , it finds this: "If Type(x) is Boolean , return the result of the comparison ToNumber(x) == y ."
As you are creating new objects with all those comparisons, all will point to different objects, hence the result will be false .
From the spec
The Abstract Equality Comparison Algorithm
The comparison x == y, where x and y are values, produces true or false. Such a comparison is performed as follows:
If Type(x) is the same as Type(y), then
a. If Type(x) is Undefined, return true.
b. If Type(x) is Null, return true.
c. If Type(x) is Number, then
i. If x is NaN, return false. ii. If y is NaN, return false. iii. If x is the same Number value as y, return true. iv. If x is +0 and y is −0, return true. v. If x is −0 and y is +0, return true. vi. Return false.
d. If Type(x) is String, then return true if x and y are exactly the same sequence of characters (same length and same characters in corresponding positions). Otherwise, return false.
e. If Type(x) is Boolean, return true if x and y are both true or both false. Otherwise, return false.
f. Return true if x and y refer to the same object. Otherwise, return false.
If x is null and y is undefined, return true.
If x is undefined and y is null, return true.
If Type(x) is Number and Type(y) is String, return the result of the comparison x == ToNumber(y).
If Type(x) is String and Type(y) is Number, return the result of the comparison ToNumber(x) == y.
If Type(x) is Boolean, return the result of the comparison ToNumber(x) == y.
If Type(y) is Boolean, return the result of the comparison x == ToNumber(y).
If Type(x) is either String or Number and Type(y) is Object, return the result of the comparison x == ToPrimitive(y).
If Type(x) is Object and Type(y) is either String or Number, return the result of the comparison ToPrimitive(x) == y.
Return false.
This is because JavaScript only compares the values in the statement "1" == 1
. The double equals sign tells JavaScript that even if the types are different, its allowed to coerce and compare the pure values.
This is why it is often advised to use the triple equals sign, to avoid this type coercion. Triple equals signs purely compare value.
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