I have some confusion about the reason that we override the .equals
method.
For example:
Test test1 = new Test(3);
Test test2 = new Test(3);
//The if comparison does the same thing that the overridden `.equals()` method does.
if(test1.equals(test2)){
System.out.println("test1 and test2 are true in .equals()");
}
// Override .equals method.
public boolean equals(Object object) {
if(object instanceof Test && ((Test)object).getValue() == this.t) {
return true;
} else {
return false;
}
}
I do not understand why we have to override the .equals()
method.
As a side note, when we override equals(), it is recommended to also override the hashCode() method. If we don't do so, equal objects may get different hash-values; and hash based collections, including HashMap, HashSet, and Hashtable do not work properly (see this for more details).
You must override hashCode() in every class that overrides equals(). Failure to do so will result in a violation of the general contract for Object. hashCode(), which will prevent your class from functioning properly in conjunction with all hash-based collections, including HashMap, HashSet, and Hashtable.
If you don't override equals, it will compare the internal address of the two references, which matches the logic behind hashCode.
As I have not overridden equals method, the default implementation will return false.
From the article Override equals and hashCode in Java:
Default implementation of equals() class provided by java.lang.Object compares memory location and only return true if two reference variable are pointing to same memory location i.e. essentially they are same object.
Java recommends to override equals and hashCode method if equality is going to be defined by logical way or via some business logic: example:
many classes in Java standard library does override it e.g. String overrides equals, whose implementation of equals() method return true if content of two String objects are exactly same
Integer wrapper class overrides equals to perform numerical comparison etc.
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