Why do bytebuffer give buffer overflow exception when buffer is not full

Question

I'm not sure why the following example gives buffer overflow exception. Hope someone can explain why, and how i can do it correctly.

It's as simple as this:

ByteBuffer bf = ByteBuffer.allocate(4);
bf.order(ByteOrder.BIG_ENDIAN);
bf.putInt(8);
bf.putInt(7); // Throws exception

The goal: [0,0,8,7]

Thanks in advance!

Answer 1

An int is 4 bytes long so you should multiply 4 to the number of int you need to store in your ByteBuffer.