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Why can't I store boost::function in std::list?

Tags:

c++

list

boost

I get the following compilation error:

error: expected `;' before 'it'"

Here's my code:

#include <boost/function.hpp>
#include <list>

template< class T >
void example() {
    std::list< boost::function<T ()> >::iterator it;
}

Why does this happen? How can I fix it?

like image 353
Nayruden Avatar asked Nov 11 '08 11:11

Nayruden


1 Answers

You need to put typename in front of that line, since the type you do ::iterator upon is dependant on the template-parameter T. Like this:

template< class T >
void example() {
    typename std::list< boost::function<T ()> >::iterator it;
}

Consider the line

std::list< boost::function<T ()> >::iterator * it; 

which could mean a multiplication, or a pointer. That's why you need typename to make your intention clear. Without it, the compiler assumes not a type, and thus it requires an operator there or a semicolon syntactically.


Also consult the new C++ FAQ entry Where to put template and typename on dependent names.

like image 108
Johannes Schaub - litb Avatar answered Oct 03 '22 02:10

Johannes Schaub - litb