I have the following code in php:
<?php
$apples = 123123;
echo "<td>
<input type='button' onclick='confirmation($apples)' value='ac/in'>
</td>";
echo('<script type="text/javascript">
function confirmation(test) {
var answer = confirm("Are you sure?")
if (answer){
alert(test);
$.get("/index.php?f=func_name_to_call",
{name: "John", hobby: "Programming"}, function(data) {});
}
}
</script>');
?>
If $apples is a number then the parameter gets passed correctly; however when it is a string, the function confirmation() is broken. Any ideas? Thanks in advance.
If you want it to pass argument as string use the below edited code
echo "<td><input type='button' onclick='confirmation(\"$apples\")' value='ac/in'></td>";
Just use \ for escaping the double quotes,and it will be considered as a string.
Yes you have to use escape character \" \" in calling confirmation function because you pass integer in a integer type parameter which is without double quotes.therefore it converts the string into integer...
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With