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Why can't C# member names be the same as the enclosing type name?

In C#, the following code doesn't compile:

class Foo {      public string Foo;  } 

The question is: why?

More exactly, I understand that this doesn't compile because (I quote):

member names cannot be the same as their enclosing type

Ok, fine. I understand that, I won't do it again, I promise.

But I really don't understand why the compiler refuses to take any field having the same name as an enclosing type. What is the underlying issue that prevents me to do that?

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Vivien Barousse Avatar asked Nov 01 '10 23:11

Vivien Barousse


Video Answer


1 Answers

Strictly speaking, this is a limitation imposed by C#, most likely for convenience of syntax. A constructor has a method body, but its member entry in IL is denoted as ".ctor" and it has slightly different metadata than a normal method (In the Reflection classes, ConstructorInfo derives from MethodBase, not MethodInfo.) I don't believe there's a .NET limitation that prevents creating a member (or even a method) with the same name as the outer type, though I haven't tried it.


I was curious, so I confirmed it's not a .NET limitation. Create the following class in VB:

Public Class Class1     Public Sub Class1()      End Sub End Class 

In C#, you reference it as:

var class1 = new Class1(); class1.Class1(); 
like image 186
Dan Bryant Avatar answered Oct 02 '22 16:10

Dan Bryant