why can't bind to 0.0.0.0:80 and 192.168.1.1:80 simultaneously?

Question

My python test code:

import socket

s1 = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s1.bind(('192.168.1.1', 80)) 
s1.listen(5)

s2 = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s2.bind(('0.0.0.0', 80)) 
s2.listen(5)

I got this error:

fpemud-workstation test # ./test.py
Traceback (most recent call last):
  File "./test.py", line 11, in <module>
    s2.bind(('0.0.0.0', 80)) 
  File "/usr/lib64/python2.7/socket.py", line 224, in meth
    return getattr(self._sock,name)(*args)
socket.error: [Errno 98] Address already in use

192.168.1.1 is the ip address of my eth0 interface.
I think 0.0.0.0:80 and 192.168.1.1:80 should be able to co-exist.
Packets with dst-addr 192.168.1.1 goes to socket s1, packets with other dst-addr goes to socket s2.

Answer 1

You cannot bind to both 0.0.0.0:80 and any other IP on port 80, because 0.0.0.0 covers every IP that exists on the machine, including your 192.168.1.1 address. It doesn't mean 'any other destination address', it means 'all interfaces on this box'.