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Is there a logical reason why E cannot implement my interface HasName?
public class SinglyLinkedList<E extends HasName> {
// stuff...
}
557
In interfaces, a class can implement more than one interface which can't be done through extends keyword.
Only generic classes can implement generic interfaces. Normal classes can't implement generic interfaces.
A class implementation of a method takes precedence over a default method. So, if the class already has the same method as an Interface, then the default method from the implemented Interface does not take effect. However, if two interfaces implement the same default method, then there is a conflict.
If both interfaces have a method of exactly the same name and signature, the implementing class can implement both interface methods with a single concrete method.
The extends keyword applies to interfaces too. That is:
public class SinglyLinkedList<E extends HasName> {
Means that E must be a type that extends a class, or implements an interface, called HasName.
It is not possible to code E implements HasName - that is implied by E extends HasName.
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