if theurl.startswith("http://"): theurl = theurl[7:] head = theurl[:theurl.find('/')] tail = theurl[theurl.find('/'):] response_code = 0 import httplib conn = httplib.HTTPConnection(head) conn.request("HEAD",tail) res = conn.getresponse() response_code = int(res.status) http://www.garageband.com/mp3cat/.UZCKbS6N4qk/01_Saraenglish.mp3 Traceback (most recent call last): File "check_data_404.py", line 51, in <module> run() File "check_data_404.py", line 35, in run res = conn.getresponse() File "/usr/lib/python2.6/httplib.py", line 950, in getresponse response.begin() File "/usr/lib/python2.6/httplib.py", line 390, in begin version, status, reason = self._read_status() File "/usr/lib/python2.6/httplib.py", line 354, in _read_status raise BadStatusLine(line) httplib.BadStatusLine
Does anyone know what "Bad Status Line" is?
Edit: I tried this for many servers, and many URL's and I still get this error?
From the documentation for httplib (Python 2) (called http.client in Python 3):
exception
httplib.
BadStatusLine
: (exceptionhttp.client.
BadStatusLine
:)A subclass of
HTTPException
.Raised if a server responds with an HTTP status code that we don’t understand.
I ran the same code and did not receive an error:
>>> theurl = 'http://www.garageband.com/mp3cat/.UZCKbS6N4qk/01_Saraenglish.mp3' >>> if theurl.startswith("http://"): ... theurl = theurl[7:] ... head = theurl[:theurl.find('/')] ... tail = theurl[theurl.find('/'):] ... >>> head 'www.garageband.com' >>> tail '/mp3cat/.UZCKbS6N4qk/01_Saraenglish.mp3' >>> response_code = 0 >>> import httplib >>> conn = httplib.HTTPConnection(head) >>> conn.request("HEAD", tail) >>> res = conn.getresponse() >>> res.status 302 >>> response_code = int(res.status)
I guess just double-check everything and try again?
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