Consider the following classes:
class A {
void print() {
System.out.println("A");
}
}
class B extends A implements C {
}
public interface C {
void print();
}
I get this error:
The inherited method A.print() cannot hide the public abstract method in C
Now, I understand that print()
must be public in order the eliminate the compilation error, but what's the reason behind this?
The answer is simple interface methods are always public or else just use composition instead of inheritance. Also to note that while overriding a method you can not narrow down the access level of the method.
The Oracle Docs says:
The access modifier public (§6.6) pertains to every kind of interface declaration.
B#print
can never be truly private, because anyone can call it via the interface:
B b = new B();
C c = b;
c.print();
Java doesn't let you pretend it's private when it is effectively public. (C++ does; different languages make different trade-offs.)
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