Why a member method of class is called before the Constructor

Question

Generally, Constructor is the very first thing to be executed in class when it's instantiated.

But in following case, A member methods of the class are executed first & then the constructor.

Why is it so?

A Code Scenario :

namespace AbsPractice
{
    class Program
    {
        static void Main(string[] args)
        {
            SavingsCustomer sc = new SavingsCustomer();
            CorporateCustomer cc = new CorporateCustomer();
        }
    }

    public abstract class Customer
    {
        protected Customer()
        {
            Console.WriteLine("Constructor of Abstract Customer");
            Print();

        }

        protected abstract void Print();
    }

    public class SavingsCustomer : Customer
    {
        public SavingsCustomer()
        {
            Console.WriteLine("Constructor  of SavingsCustomer");
        }


        protected override void Print()
        {
            Console.WriteLine("Print() Method of SavingsCustomer");
        }
    }

    public class CorporateCustomer : Customer
    {
        public CorporateCustomer()
        {
            Console.WriteLine("Constructor of CorporateCustomer");
        }


        protected override void Print()
        {
            Console.WriteLine("Print() Method of CorporateCustomer");
        }
    }
}

Answer 1

That's because when you call SavingsCustomer ctor, first of all its base class ctor is called; in Customer ctor you call Print that's an overridden method.
So basicly before SavingsCustomer ctor instructions are executed, Customer ctor must be completely called. Note that when you call Print from Customer, SavingsCustomer.Print() is executed.

This is the expected behaviour; if you want your classes to behave differently, you must change their logic. Maybe you shouldn't call an abstract method from base constructor, just to avoid what you're seeing now...