Which numpy versions are compatible with Tensorflow 1.14.0

Question

I'm getting warnings combining 1.14.0 with numpy 1.17.2. Do these go together? I can't find any official TF page stating compatibility requirements.

Answer 1

Please downgrade numpy version from 1.17.2 to 1.16.4 will resolve issue with Tensorflow 1.14.0

Here am able to replicate issue

import tensorflow as tf
print(tf.__version__)
import numpy as np
print(np.__version__)

Output:

/usr/local/lib/python3.6/dist-packages/tensorflow/python/framework/dtypes.py:516: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint8 = np.dtype([("qint8", np.int8, 1)])
/usr/local/lib/python3.6/dist-packages/tensorflow/python/framework/dtypes.py:517: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint8 = np.dtype([("quint8", np.uint8, 1)])
/usr/local/lib/python3.6/dist-packages/tensorflow/python/framework/dtypes.py:518: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint16 = np.dtype([("qint16", np.int16, 1)])
/usr/local/lib/python3.6/dist-packages/tensorflow/python/framework/dtypes.py:519: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint16 = np.dtype([("quint16", np.uint16, 1)])
/usr/local/lib/python3.6/dist-packages/tensorflow/python/framework/dtypes.py:520: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint32 = np.dtype([("qint32", np.int32, 1)])
/usr/local/lib/python3.6/dist-packages/tensorflow/python/framework/dtypes.py:525: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  np_resource = np.dtype([("resource", np.ubyte, 1)])

1.14.0
1.17.2

To fix this, please execute below code to downgrade numpy to 1.16.4

pip uninstall numpy
pip install numpy==1.16.4

After that, please restart your runtime and execute below code

import tensorflow as tf
print(tf.__version__)
import numpy as np
print(np.__version__)

Output:

1.14.0
1.16.4

Answer 2

Those who are looking for tensorflow2 and numpy compatible versions. They work fine together.

Tensorflow 2.4.1
numpy 1.19.5