when using super().method, which methods is called in this situation

Question

Suppose you have an object of type BlahChild that is an extension of BlahParent, what happens when BlahChild calls super().someMethod and someMethod contains a call to another function, anotherMethod() that is also overriden in BlahChild?

Does BlahChild's anotherMethod get called, or BlahParent's anotherMethod?

Answer 1

Non-static methods are always virtual in java, so yes.

From wikipedia:

In Java, all non-static methods are by default "virtual functions." Only methods marked with the keyword final, which cannot be overridden, along with private methods, which are not inherited, are non-virtual.

It will call the BlahChilds implementation.

Example:

class Parent {
    public void method() {
        System.out.println("Parent: method");
    someOtherMethod();
    }
    public void someOtherMethod() {
        System.out.println("Parent: some other");
    }
}


class Child extends Parent {

    @Override
    public void method() {
        System.out.println("Child: method");
        super.method();
    }

    @Override
    public void someOtherMethod() {
        System.out.println("Child: some other");
    }
}

public class Test {
    public static void main(String[] args) {
        new Child().method();
    }
}

Output:

Child: method
Parent: method
Child: some other   // <-- Child.someOtherMethod gets called, from Parent.method