I understand what the double not operator does in JavaScript. I'm curious about it's use though and whether or not a recent assertion that I made is correct.
I said that if (!!someVar)
is never meaningful nor is (!!someVar && ...
because both the if
and the &&
will cause someVar to be evaluated as a boolean so the !! is superfluous.
In fact, the only time that I could think of that it would be legitimate to use the double not operator is if you wanted to do a strict comparison to another boolean value (so maybe in return value that expects true or false explicitly).
Is this correct? I started to doubt myself when I noticed jQuery 1.3.2 used both if (!!someVar)
and return !!someVar && ...
Does the double not have any actual effect in these situations?
My personal opinion is that it just leads to confusion. If I see an if statement, I know it's evaluating it as a boolean.
The double negation(!!) operator calculates the truth value of a value. This operator returns a boolean value, which depends on the truthiness of the given expression.
In Boolean algebra, the NOT operator is a Boolean operator that returns TRUE or 1 when the operand is FALSE or 0, and returns FALSE or 0 when the operand is TRUE or 1. Essentially, the operator reverses the logical value associated with the expression on which it operates.
If you have ever noticed a double exclamation mark (!!) in someone's JavaScript code you may be curious what it's for and what it does. It's really simple: it's short way to cast a variable to be a boolean (true or false) value.
Double-negation turns a "truthy" or "falsy" value into a Boolean value, true or false .
In the context of if
statements I'm with you, it is completely safe because internally, the ToBoolean
operation will be executed on the condition expression (see Step 3 on the spec).
But if you want to, lets say, return a boolean value from a function, you should ensure that the result will be actually boolean, for example:
function isFoo () { return 0 && true; } console.log(isFoo()); // will show zero typeof isFoo() == "number";
In conclusion, the Boolean Logical Operators can return an operand, and not a Boolean
result necessarily:
The Logical AND operator (&&
), will return the value of the second operand if the first is truly:
true && "foo"; // "foo"
And it will return the value of the first operand if it is by itself falsy:
NaN && "anything"; // NaN 0 && "anything"; // 0
On the other hand, the Logical OR operator (||
) will return the value of the second operand, if the first one is falsy:
false || "bar"; // "bar"
And it will return the value of the first operand if it is by itself non-falsy:
"foo" || "anything"; // "foo"
Maybe it's worth mentioning that the falsy values are: null
, undefined
, NaN
, 0
, zero-length string, and of course false
.
Anything else (that is not falsy, a Boolean
object or a Boolean
value), evaluated in boolean context, will return true
.
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