When I catch an exception, how do I get the type, file, and line number?

Question

Catching an exception that would print like this:

Traceback (most recent call last):   File "c:/tmp.py", line 1, in <module>     4 / 0 ZeroDivisionError: integer division or modulo by zero 

I want to format it into:

ZeroDivisonError, tmp.py, 1 

Answer 1

import sys, os  try:     raise NotImplementedError("No error") except Exception as e:     exc_type, exc_obj, exc_tb = sys.exc_info()     fname = os.path.split(exc_tb.tb_frame.f_code.co_filename)[1]     print(exc_type, fname, exc_tb.tb_lineno) 

Answer 2

Simplest form that worked for me.

import traceback  try:     print(4/0) except ZeroDivisionError:     print(traceback.format_exc()) 

Output

Traceback (most recent call last):   File "/path/to/file.py", line 51, in <module>     print(4/0) ZeroDivisionError: division by zero  Process finished with exit code 0