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When does the vptr (pointing to vtable) get initialized for a polymorphic class?

This is not about "When VTABLE is created?". Rather, when the VPTR should be initialized? Is it at the beginning/end of the constructor or before/after the constructor?

A::A () : i(0), j(0)  -->> here ?
{
  -->> here ?
  //...
  -->> here ?
}
like image 948
iammilind Avatar asked Jul 06 '11 05:07

iammilind


People also ask

What is VPTR vtable pointer?

The compiler places the addresses of the virtual functions for that particular class in the VTABLE. In each class with virtual functions, it secretly places a pointer, called the vpointer (abbreviated as VPTR), which points to the VTABLE for that object.

What is the difference between vtable and VPTR?

# Vtable is created by compiler at compile time. # VPTR is a hidden pointer created by compiler implicitly. # If base class pointer pointing to a function which is not available in base class then it will generate error over there. # Memory of Vtable and VPTR gets allocated inside the process address space.

How is vtable created?

The vtable is created at compile time. When a new object is created during run time, the hidden vtable pointer is set to point to the vtable. Keep in mind, though, that you can't make reliable use if the virtual functions until the object is fully constructed. (No calling virtual functions in the constructor.)

How does C++ vtable work?

For every class that contains virtual functions, the compiler constructs a virtual table, a.k.a vtable. The vtable contains an entry for each virtual function accessible by the class and stores a pointer to its definition. Only the most specific function definition callable by the class is stored in the vtable.


2 Answers

The machinery for virtual calls (usually a v-table, but doesn't need to be) is set up during the ctor-initializer, after construction of base subobjects and before construction of members. Section [class.base.init] decrees:

Member functions (including virtual member functions, 10.3) can be called for an object under construction. Similarly, an object under construction can be the operand of the typeid operator (5.2.8) or of a dynamic_cast (5.2.7). However, if these operations are performed in a ctor-initializer (or in a function called directly or indirectly from a ctor-initializer) before all the mem-initializers for base classes have completed, the result of the operation is undefined.

Actually, during construction of the base subobjects, the virtual function machinery exists, but it is set up for the base class. Section [class.cdtor] says:

Member functions, including virtual functions (10.3), can be called during construction or destruction (12.6.2). When a virtual function is called directly or indirectly from a constructor or from a destructor, including during the construction or destruction of the class’s non-static data members, and the object to which the call applies is the object (call it x) under construction or destruction, the function called is the final overrider in the constructor’s or destructor’s class and not one overriding it in a more-derived class. If the virtual function call uses an explicit class member access (5.2.5) and the object expression refers to the complete object of x or one of that object’s base class subobjects but not x or one of its base class subobjects, the behavior is undefined.

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Ben Voigt Avatar answered Nov 15 '22 14:11

Ben Voigt


it's initialized between the constructors of base and derived classes:

class Base { Base() { } virtual void f(); };
class Derived { Derived(); virtual void f(); };

It happens when raw memory is converted to Base object. It happens when Base object is converted to Derived object during construction of an object. Same obviously happens in reverse when destroying object. I.e. every time when type changes, the vtable pointer is changed. (I'm sure someone comments that vtables don't need to exists according to the std..)

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tp1 Avatar answered Nov 15 '22 13:11

tp1