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When do function-level static variables get allocated/initialized?

Tags:

c++

variables

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How are static variables initialized?

Static variables are initialized only once , at the start of the execution. These variables will be initialized first, before the initialization of any instance variables. A single copy to be shared by all instances of the class. A static variable can be accessed directly by the class name and doesn't need any object.

Can we initialize static variable in function?

Inside a function, you can initialize a static variable using the static keyword.

Are static variables initialized to zero in Java?

Variable in a Static Block In this case, the variable initialization will be in sequence. For instance, the JVM initially assigns variable z to a default int value of 0. Then, in the static block, it is changed to 30.

Are static variables initialized C++?

We learned about static variables that are declared in a C++ program. We know that static variables are initialized only once and they retain the value throughout the program.


I was curious about this so I wrote the following test program and compiled it with g++ version 4.1.2.

include <iostream>
#include <string>

using namespace std;

class test
{
public:
        test(const char *name)
                : _name(name)
        {
                cout << _name << " created" << endl;
        }

        ~test()
        {
                cout << _name << " destroyed" << endl;
        }

        string _name;
};

test t("global variable");

void f()
{
        static test t("static variable");

        test t2("Local variable");

        cout << "Function executed" << endl;
}


int main()
{
        test t("local to main");

        cout << "Program start" << endl;

        f();

        cout << "Program end" << endl;
        return 0;
}

The results were not what I expected. The constructor for the static object was not called until the first time the function was called. Here is the output:

global variable created
local to main created
Program start
static variable created
Local variable created
Function executed
Local variable destroyed
Program end
local to main destroyed
static variable destroyed
global variable destroyed

Some relevant verbiage from C++ Standard:

3.6.2 Initialization of non-local objects [basic.start.init]

1

The storage for objects with static storage duration (basic.stc.static) shall be zero-initialized (dcl.init) before any other initialization takes place. Objects of POD types (basic.types) with static storage duration initialized with constant expressions (expr.const) shall be initialized before any dynamic initialization takes place. Objects of namespace scope with static storage duration defined in the same translation unit and dynamically initialized shall be initialized in the order in which their definition appears in the translation unit. [Note: dcl.init.aggr describes the order in which aggregate members are initialized. The initialization of local static objects is described in stmt.dcl. ]

[more text below adding more liberties for compiler writers]

6.7 Declaration statement [stmt.dcl]

...

4

The zero-initialization (dcl.init) of all local objects with static storage duration (basic.stc.static) is performed before any other initialization takes place. A local object of POD type (basic.types) with static storage duration initialized with constant-expressions is initialized before its block is first entered. An implementation is permitted to perform early initialization of other local objects with static storage duration under the same conditions that an implementation is permitted to statically initialize an object with static storage duration in namespace scope (basic.start.init). Otherwise such an object is initialized the first time control passes through its declaration; such an object is considered initialized upon the completion of its initialization. If the initialization exits by throwing an exception, the initialization is not complete, so it will be tried again the next time control enters the declaration. If control re-enters the declaration (recursively) while the object is being initialized, the behavior is undefined. [Example:

      int foo(int i)
      {
          static int s = foo(2*i);  // recursive call - undefined
          return i+1;
      }

--end example]

5

The destructor for a local object with static storage duration will be executed if and only if the variable was constructed. [Note: basic.start.term describes the order in which local objects with static storage duration are destroyed. ]


The memory for all static variables is allocated at program load. But local static variables are created and initialized the first time they are used, not at program start up. There's some good reading about that, and statics in general, here. In general I think some of these issues depend on the implementation, especially if you want to know where in memory this stuff will be located.


The compiler will allocate static variable(s) defined in a function foo at program load, however the compiler will also add some additional instructions (machine code) to your function foo so that the first time it is invoked this additional code will initialize the static variable (e.g. invoking the constructor, if applicable).

@Adam: This behind the scenes injection of code by the compiler is the reason for the result you saw.


I try to test again code from Adam Pierce and added two more cases: static variable in class and POD type. My compiler is g++ 4.8.1, in Windows OS(MinGW-32). Result is static variable in class is treated same with global variable. Its constructor will be called before enter main function.

  • Conclusion (for g++, Windows environment):
  1. Global variable and static member in class: constructor is called before enter main function (1).
  2. Local static variable: constructor is only called when execution reaches its declaration at first time.
  3. If Local static variable is POD type, then it is also initialized before enter main function (1). Example for POD type: static int number = 10;

(1): The correct state should be: "before any function from the same translation unit is called". However, for simple, as in example below, then it is main function.

#include <iostream>                     
#include <string>

using namespace std;

class test
{
public:
   test(const char *name)
            : _name(name)
    {
            cout << _name << " created" << endl;
    }

    ~test()
    {
            cout << _name << " destroyed" << endl;
    }

    string _name;
    static test t; // static member
 };
test test::t("static in class");

test t("global variable");

void f()
{
    static  test t("static variable");
    static int num = 10 ; // POD type, init before enter main function
    
    test t2("Local variable");
    cout << "Function executed" << endl;
}

int main()
{
    test t("local to main");
    cout << "Program start" << endl;
    f();
    cout << "Program end" << endl;
    return 0;
 }

result:

static in class created
global variable created
local to main created
Program start
static variable created
Local variable created
Function executed
Local variable destroyed
Program end
local to main destroyed
static variable destroyed
global variable destroyed
static in class destroyed

Anybody tested in Linux env ?