I'm attempting to write a heapsort method in java but it's not working exactly as I want it to:
public class HeapSort {
private static int n;
private static void swap(int[] A, int a, int b)
{
int tmp = A[a];
A[a] = A[b];
A[b] = tmp;
}
private static void insert(int[] A, int i)
{
int left = i * 2;
int right = left + 1;
int max = i;
if (left <= n && A[left] < A[max]){
max = left;
}
if (right <= n && A[right] > A[max]) {
max = right;
}
if (max != i) {
swap(A, i, max);
insert(A, max);
}
}
public static void HeapSort(int[] A)
{
n = A.length - 1;
for (int i = n / 2; i >= 0; i--)
insert(A, i);
for (int i = n; i > 0; i--) {
swap(A, 0, i);
n--;
insert(A, 0);
}
}
public static void main(String[] args){
int[] A = new int[] {9, 2, 8, 1, 4};
System.out.println(java.util.Arrays.toString(arr));
HeapSort(A);
System.out.println(java.util.Arrays.toString(arr));
}
}
It works with some arrays however arrays like 9, 2, 8, 1, 4 will get sorted into 1, 4, 2, 8, 9. So why isn't it sorting the array in the correct way?
Heap sort is a comparison-based sorting technique based on Binary Heap data structure. It is similar to the selection sort where we first find the minimum element and place the minimum element at the beginning. Repeat the same process for the remaining elements. Heap sort is an in-place algorithm.
Heapsort has a worst- and average-case running time of O ( n log n ) O(n \log n) O(nlogn) like mergesort, but heapsort uses O ( 1 ) O(1) O(1) auxiliary space (since it is an in-place sort) while mergesort takes up O ( n ) O(n) O(n) auxiliary space, so if memory concerns are an issue, heapsort might be a good, fast ...
if (left <= n && A[left] > A[i]){
max = left;
}
Try this and see. I have made the complete program as below. This works fine for input you provided.
public class HeapSort {
private static int n;
private static void swap(int[] A, int a, int b)
{
int tmp = A[a];
A[a] = A[b];
A[b] = tmp;
}
private static void insert(int[] A, int i)
{
int left = i * 2;
int right = left + 1;
int max = i;
if (left <= n && A[left] > A[i]){
max = left;
}
if (right <= n && A[right] > A[max]) {
max = right;
}
if (max != i) {
swap(A, i, max);
insert(A, max);
}
}
public static void HeapSort(int[] A)
{
n = A.length - 1;
for (int i = n / 2; i >= 0; i--)
insert(A, i);
for (int i = n; i > 0; i--) {
swap(A, 0, i);
n--;
insert(A, 0);
}
}
public static void main(String[] args){
int[] A = new int[] {19, 6, 28, 1, 0};
int[] B = new int[] {1, 2, 4, 8, 9, 0};
System.out.println(java.util.Arrays.toString(A));
System.out.println(java.util.Arrays.toString(B));
HeapSort(A);
HeapSort(B);
System.out.println(java.util.Arrays.toString(A));
System.out.println(java.util.Arrays.toString(B));
}
}
Here is the output.
[19, 6, 28, 1, 0]
[1, 2, 4, 8, 9, 0]
[0, 1, 6, 19, 28]
[0, 1, 2, 4, 8, 9]
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