What's the syntax of the following in c?

Question

fd1 = open("/dev/test_kft" "1",00);

What does "/dev/test_kft" "1" mean?

Answer 1

It's implicit concatenation as performed by the compiler. It results in "/dev/test_kft1".

Answer 2

The preprocessor concatenates adjacent string literals, so that line is the same as

fd1 = open("/dev/test_kft1", 00);