In an example of "C Primer Plus", the author has used %ul
format specifier (in both scanf and printf) for unsigned long. When I try to generalize the problem, it seems that the %ul
makes something wrong in my computer. But using %lu
solved the issue.
Actually, rather than focusing on the problem and the line of codes, I want to know about the difference between %ul
and %lu
. Maybe I could figure out what's wrong.
Searching doesn't give me something useful (except that "they are different").
Any explanation or link/reference is appreciated.
%lu. Unsigned int or unsigned long. %lli or %lld.
%d is a signed integer, while %u is an unsigned integer. Pointers (when treated as numbers) are usually non-negative. If you actually want to display a pointer, use the %p format specifier.
%f %f represents the data in normal decimal form, upto six decimal places, although you can control, that upto how many decimal places did you want your output. %g %g represents the decimal format of the answer, depending upon whose length is smaller, comparing between %e and %f. Also removes succeeding zeros.
%lu
is correct, while %ul
is incorrect.
A printf
format specifier follows the form %[flags][width][.precision][length]specifier
.
u
is a specifier meaning "unsigned decimal integer".
l
is a length modifier meaning "long".
The length modifier should go before the conversion specifier, which means %lu
is correct.
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