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What's the difference between String.matches and Matcher.matches?

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java

What's the difference between String.matches and Matcher.matches? Is there any difference in terms of performance or other things?

like image 381
Winston Chen Avatar asked Mar 18 '10 11:03

Winston Chen


3 Answers

Absolutely. A Matcher is created on on a precompiled regexp, while String.matches must recompile the regexp every time it executes, so it becomes more wasteful the more often you run that line of code.

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Kilian Foth Avatar answered Nov 19 '22 10:11

Kilian Foth


String.matches internally delegates to Matcher.matches.

public boolean matches(String regex) {
    return Pattern.matches(regex, this);
}

public static boolean matches(String regex, CharSequence input) {
    Pattern p = Pattern.compile(regex);
    Matcher m = p.matcher(input);
    return m.matches();
}

If you are reusing the Pattern object then there will be some performance benefit. Also when using Pattern/Matcher you can group your regular expressions and get the matching parts.

The bottomline is if you have a regex that you will use only once and you don't need to parse your string to get matching parts then use either. But if you are going to use the same regex against multiple strings or you need parts of the String based on regex create a Pattern and get Matcher using it.

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saugata Avatar answered Nov 19 '22 10:11

saugata


Out of curiosity I did this small test on the time differences. Turns out that using a pre-compiled pattern is more than 5 times faster than using String.matches method.

import java.util.regex.Pattern;

/**
 * @author Rajind Ruparathna
 */
public class MatchesTest {
    public static void main(String Args[]) {
        String first = "@\\{message.headers\\.?([^\\}]*)\\}";
        String second = "@\\{message.headers.wolla\\}";
        long start, end, total;
        float avg;
        int NUM_OF_ITERATIONS = 100;

        Pattern pattern = Pattern.compile(first);

        total = 0;
        start = 0;
        end = 0;
        avg = 0;

        for (int i=0; i< NUM_OF_ITERATIONS; i++) {
            start = System.nanoTime();
            pattern.matcher(second).matches();
            end = System.nanoTime();
            total = total + (end - start);
        }
        avg = total/NUM_OF_ITERATIONS;
        System.out.println("Duration pre compiled: " + avg);

        total = 0;
        start = 0;
        end = 0;
        avg = 0;

        for (int i=0; i< NUM_OF_ITERATIONS; i++) {
            start = System.nanoTime();
            first.matches(second);
            end = System.nanoTime();
            total = total + (end - start);
        }
        avg = total/NUM_OF_ITERATIONS;
        System.out.println("In place compiled: " + avg);
    }
}

Output (nanoseconds):

Duration pre compiled: 4505.0

In place compiled:    44960.0

P.S. This test is a quick and dirty test and may not be according to performance benchmarking practises. If you want to get highly accurate results please use a micro benchmarking tool.

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Rajind Ruparathna Avatar answered Nov 19 '22 11:11

Rajind Ruparathna