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Size_t is defined as an unsigned integer, but the size of it depends on whether you're on a 32 or 64-bit machine. What's the correct and portable way to print out a size_t?
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C++ printf is a formatting function that is used to print a string to stdout. The basic idea to call printf in C++ is to provide a string of characters that need to be printed as it is in the program. The printf in C++ also contains a format specifier that is replaced by the actual value during execution.
size_t type is a base unsigned integer type of C/C++ language. It is the type of the result returned by sizeof operator. The type's size is chosen so that it can store the maximum size of a theoretically possible array of any type. On a 32-bit system size_t will take 32 bits, on a 64-bit one 64 bits.
Generally, printf() function is used to print the text along with the values. If you want to print % as a string or text, you will have to use '%%'. Neither single % will print anything nor it will show any error or warning.
Try using the %zu format string
size_t val = get_the_value(); printf("%zu",val); The z portion is a length specifier which says the argument will be size_t in length.
Source - http://en.wikipedia.org/wiki/Printf#printf_format_placeholders
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