What's the best way of distinguishing bools from numbers in Python?

Question

I have an application where I need to be able to distinguish between numbers and bools as quickly as possible. What are the alternatives apart from running isinstance(value, bool) first?

Edit: Thanks for the suggestions. Actually, what I want to be able to do have a check for numbers that leaves out bools so that I can reorder my checks (numbers are far more prevalent) and improve my negacalls. isinstance() itself is fast enough. The x is True or x is False is intriguing.

Answer 1

So, Padraic Cunningham suggests, that the following might be a bit faster. My own quick experiments with cProfile-ing it haven't shown any difference:

isbool = value is True or value is False

I assume that's as fast as you can get: Two non-type-coercing comparisons.

Edit: I replayed the timing tests from @user 5061 and added my statement. This is my result:

>>> import timeit
>>> stmt1 = "isinstance(123, bool)"
>>> stmt2 = "123 is True or 123 is False"
>>> t1 = timeit.timeit(stmt1)
>>> t2 = timeit.timeit(stmt2)
>>> print t1
0.172112941742
>>> print t2
0.0690350532532

Edit 2: Note, that I'm using Python 2.7 here. @user 5061 might use Python 3 (telling from the print() function), so any solution provided here should be tested by OP before putting in production, for YMMV.