Is there a really large variable type I can use in Java to store huge numbers (up to around forty digits)?
long
's maximum value is 9223372036854775807, which is 19 digits -- not nearly large enough.
I'm trying to create a calculator that can handle large numbers, because most nowadays can only hold an insufficient 10 digits or so, and I want want accurate calculations with numbers of a much larger magnitude
EDIT
Thanks for the answers. I can use BigInteger
for big integers, the only limit being the computer's memory (should be sufficient). For decimals, I'll use float
^e, as @WebDaldo suggested, or BigDecimal
(similar to BigInteger), as @kocko suggested.
Use the static valueOf method to turn an ordinary number into a big number: BigInteger a = BigInteger. valueOf(100);
Long can store 10 digit easily. Long phoneNumber = 1234567890; It can store more than that also. This means it can store values of range 9,223,372,036,854,775,807 to -9,223,372,036,854,775,808.
You can use BigInteger class.
BigInteger bi1 = new BigInteger("637824629384623845238423545642384");
BigInteger bi2 = new BigInteger("3039768898793547264523745379249934");
BigInteger bigSum = bi1.add(bi2);
BigInteger bigProduct = bi1.multiply(bi2);
System.out.println("Sum : " + bigSum);
System.out.println("Product : " + bigProduct);
Output:
Sum : 3677593528178171109762168924892318
Product : 1938839471287900434078965247064711159607977007048190357000119602656
I should mention BigDecimal, which is excellent for amount calculations compare to double.
BigDecimal bd = new BigDecimal("123234545.4767");
BigDecimal displayVal = bd.setScale(2, RoundingMode.HALF_EVEN);
NumberFormat usdFormat = NumberFormat.getCurrencyInstance(Locale.US);
System.out.println(usdFormat.format(displayVal.doubleValue()));
Output:
$123,234,545.48
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