What type of variable that contain lambda [duplicate]

Question

Can you explain which type of L in this context. In other words what type I can use instead auto keyword?

int main(){
 int x=0;
 auto L = [x] (int y)->bool{
   return x>y;
 };
  return 0; 
}

Answer 1

There is nothing in C++11 which you could use instead of auto in this context that would mean the exact same type. That's because the type of each lambda expression is a unique, unnamed type. Quoting C++11 5.1.2/3:

The type of the lambda-expression (which is also the type of the closure object) is a unique, unnamed non-union class type — called the closure type — whose properties are described below. ...