What to do when you need to store a (very) large number?

Question

I am trying to do a Project Euler problem but it involves adding the digits of a very large number. (100!)

Using Java int and long are too small.

Thanks for any suggestions

Answer 1

Class BigInteger looks like it might be what you are looking for.

Answer 2

Use BigInteger. Here is an example from the book Java Examples in a Nutshell that involves computing factorials, with caching.

import java.math.BigInteger;
import java.util.ArrayList;

/*
 * Copyright (c) 2000 David Flanagan.  All rights reserved.
 * This code is from the book Java Examples in a Nutshell, 2nd Edition.
 * It is provided AS-IS, WITHOUT ANY WARRANTY either expressed or 
 * implied. You may study, use, and modify it for any non-commercial 
 * purpose. You may distribute it non-commercially as long as you 
 * retain this notice. For a commercial use license, or to purchase 
 * the book (recommended), visit 
 * http://www.davidflanagan.com/javaexamples2.
 */

/**
 * This program computes and displays the factorial of a number 
 * specified on the command line. It handles possible user input 
 * errors with try/catch.
 */
public class FactComputer {
  public static void main(String[] args) {
    // Try to compute a factorial.
    // If something goes wrong, handle it in the catch clause below.
    try {
      int x = Integer.parseInt(args[0]);
      System.out.println(x + "! = " + Factorial4.factorial(x));
    }
    // The user forgot to specify an argument.
    // Thrown if args[0] is undefined.
    catch (ArrayIndexOutOfBoundsException e) {
      System.out.println("You must specify an argument");
      System.out.println("Usage: java FactComputer <number>");
    }
    // The argument is not a number. Thrown by Integer.parseInt().
    catch (NumberFormatException e) {
      System.out.println("The argument you specify must be an integer");
    }
    // The argument is < 0. Thrown by Factorial4.factorial()
    catch (IllegalArgumentException e) {
      // Display the message sent by the factorial() method:
      System.out.println("Bad argument: " + e.getMessage());
    }
  }
}

/**
 * This version of the program uses arbitrary precision integers, so it 
 * does not have an upper-bound on the values it can compute. It uses an 
 * ArrayList object to cache computed values instead of a fixed-size 
 * array. An ArrayList is like an array, but can grow to any size. The 
 * factorial() method is declared "synchronized" so that it can be safely 
 * used in multi-threaded programs. Look up java.math.BigInteger and
 * java.util.ArrayList while studying this class.
 * Prior to Java 1.2, use Vector instead of ArrayList
 */

class Factorial4 {
  protected static ArrayList table = new ArrayList(); // create cache
  static { // Initialize the first element of the cache with !0 = 1.
    table.add(BigInteger.valueOf(1));
  }

  /** The factorial() method, using BigIntegers cached in a ArrayList */
  public static synchronized BigInteger factorial(int x) {
    if (x < 0)
      throw new IllegalArgumentException("x must be non-negative.");
    for (int size = table.size(); size <= x; size++) {
      BigInteger lastfact = (BigInteger) table.get(size - 1);
      BigInteger nextfact = lastfact.multiply(BigInteger.valueOf(size));
      table.add(nextfact);
    }
    return (BigInteger) table.get(x);
  }

  /**
   * A simple main() method that we can use as a standalone test 
   * program for our factorial() method.
   */
  public static void main(String[] args) {
    for (int i = 0; i <= 50; i++)
      System.out.println(i + "! = " + factorial(i));
  }
}

Answer 3

java.lang.BigInteger or java.lang.BigDecimal