In TypeScript, what exactly is type '{}'
and how does it relate to other built-in types?
For example, the last line of the following example gives Type '{}' is not assignable to type 'number'
, and I am not completely clear on what type {}
is in this context, or indeed how it comes about:
// A function taking no arguments and returning T
type NoArgsFn<T> = () => T;
// An instance of NoArgsFn<number>
function get_the_answer(): number {
return 42;
}
// Call the supplied function and return its value
function call<T, Fn extends NoArgsFn<T>>(fn: Fn): T {
return fn();
}
// Expect this to be equivalent to `let the_answer: number = 42', but
// instead get "Type '{}' is not assignable to type 'number'"
let the_answer: number = call(get_the_answer);
1. a number of things or persons sharing a particular characteristic, or set of characteristics, that causes them to be regarded as a group, more or less precisely defined or designated; class; category. a criminal of the most vicious type.
The definition of a type means people, places or things that share traits which allow them to belong to the same group. An example of type is men with blond hair.
1. To type or typing means to input characters into a computer using a keyboard.
Sort, type and kind all generally mean the same thing. They are words we use to refer to a group of people or things which share the same characteristics. We use these words very often when we describe things and we often find them in dictionary definitions: Jazz isn't the sort of music I can listen to for very long.
type {}
Consider the object type { id: number, name: string }
, which represents a 2-field object. Legal values of this type include { id: 1, name: "Foo" }
and { id: 2, name: "Bar" }
.
The type object {}
represents a 0-field object. The only legal value of this type is an empty object: {}
.
So the value { id: 1, name: "Foo" }
is of type { id: number, name: string }
, and the value {}
(i.e. an empty object) is of type {}
.
The error seems to be a bug in the TypeScript compiler (I submitted an issue here). It fails to infer the type arguments in the call to call
. You can work around this by explicitly specifying the type arguments:
let the_answer: number = call<number, NoArgsFn<number>>(get_the_answer);
But it's simpler and more straightforward to use a single type argument instead, as @NitzanTomer suggested:
function call<T>(fn: NoArgsFn<T>): T {
return fn();
}
EDIT: I issue I submitted was closed as a duplicate of #7234 which is to be fixed before the release of TypeScript 2.0.
You need to have your call function like this:
function call<T>(fn: NoArgsFn<T>): T {
return fn();
}
In your original call
function you had 2 generic types which you did not pass when calling the function and the compiler failed to infer what types they are.
Type {}
is an object literal (as far as I'm aware), and so you can face the same error like this:
var o = {};
var n: number = o; // Error: Type '{}' is not assignable to type 'number'
I'm not exactly sure why the compiler inferred that the function returns {}
in your example.
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