What is the syntax for Typescript arrow functions with generics?

Question

The typescript handbook currently has nothing on arrow functions. Normal functions can be generically typed with this syntax: example:

function identity<T>(arg: T): T {
    return arg;
}

What is the syntax for arrow functions?

Answer 1

Edit

Per @Thomas comment, in newer TS compilers, we can simply do:

const foo = <T,>(x: T) => x;

Original Answer

The full example explaining the syntax referenced by Robin... brought it home for me:

Generic functions

Something like the following works fine:

function foo<T>(x: T): T { return x; }

However using an arrow generic function will not:

const foo = <T>(x: T) => x; // ERROR : unclosed `T` tag

Workaround: Use extends on the generic parameter to hint the compiler that it's a generic, e.g.:

const foo = <T extends unknown>(x: T) => x;

Answer 2

If you're in a .tsx file you cannot just write <T>, but this works:

const foo = <T, >(x: T) => x;

As opposed to the extends {} hack, this hack at least preserves the intent.