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In the following code:
Expression<Func<int, bool>> isOdd = i => (i & 1) == 1;
...what is the meaning of (i & 1) == 1?
799
asked Mar 15 '09 09:03
Bitwise AND. In this case, checking whether the last bit in i is set. If it is, it must be an odd number since the last bit represents 1 and all other bits represent even numbers.
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