What is the "Illegal Instruction: 4" error and why does "-mmacosx-version-min=10.x" fix it?

Question

I get Illegal Instruction: 4 errors with binaries compiled with GCC 4.7.2 under Mac OS X 10.8.2 ("Mountain Lion"), when those binaries are run under Mac OS X 10.7.x ("Lion") and earlier versions. The binaries work properly under Mac OS X 10.8.x.

I added -mmacosx-version-min=10.5 to my compile flags and this seems to help resolve the issue for 10.5.x, 10.6.x and 10.7.x clients, whatever that issue is.

Which gets to my question(s):

• What is the Illegal Instruction: 4 error?
• Why does -mmacosx-version-min=10.x fix this specific error on 10.x and greater clients?

I'd like to apply this fix to my makefiles, but would like to know what it is doing before I pull the trigger. (Will I have larger binaries? Do I still have 64-bit binaries? Are there gotchas with this approach I should know about? Unintended side-effects? Etc.)

Answer 1

From the Apple Developer Forum (account required):

"The compiler and linker are capable of using features and performing optimizations that do not work on older OS versions. -mmacosx-version-min tells the tools what OS versions you need to work with, so the tools can disable optimizations that won't run on those OS versions. If you need to run on older OS versions then you must use this flag.

"The downside to -mmacosx-version-min is that the app's performance may be worse on newer OS versions then it could have been if it did not need to be backwards-compatible. In most cases the differences are small."

Answer 2

The "illegal instruction" message is simply telling you that your binaries contain instructions the version of the OS that you are attempting to run them under does not understand. I can't give you the precise meaning of 4 but I expect that is internal to Apple.

Otherwise take a look at these... they are a little old, but probably tell you what you need to know

How does 64 bit code work on OS-X 10.5?
what does macosx-version-min imply?