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What is the GOMAXPROCS default value?

Tags:

go

runtime

Is it guaranteed that GOMAXPROCS is set to 1 when the environment variable of the same name is not set?

This code shows the value:

package main

import (
    "runtime"
    "fmt"
)

func getGOMAXPROCS() int {
    return runtime.GOMAXPROCS(0)
}

func main() {
    fmt.Printf("GOMAXPROCS is %d\n", getGOMAXPROCS())
}

and running it like this:

$ GOMAXPROCS= go run max.go 
GOMAXPROCS is 1

shows that it is 1 in this case, but I am looking for some confirmation here.

like image 617
mnagel Avatar asked Jul 25 '13 09:07

mnagel


3 Answers

UPDATE 2018: By default, Go programs run with GOMAXPROCS set to the number of cores available; in prior releases it defaulted to 1.

Starting from Go 1.5, the default value is the number of cores. You only need to explicitly set it if you are not okay with this in newer Go versions.


No, there's no guarantee about what the default is; even though all known implementations use the value '1'. If your code, in absence of the environment variable, requires a specific default value then you should set it in code. Additionally:

GOMAXPROCS sets the maximum number of CPUs that can be executing simultaneously and returns the previous setting. If n < 1, it does not change the current setting. The number of logical CPUs on the local machine can be queried with NumCPU. This call will go away when the scheduler improves.

(Emphasis mine)

like image 149
zzzz Avatar answered Nov 13 '22 07:11

zzzz


As Go 1.5 Release Notes says

By default, Go programs run with GOMAXPROCS set to the number of cores available; in prior releases it defaulted to 1.

So starting from Go 1.5, the default value should be the number of cores.

like image 37
laike9m Avatar answered Nov 13 '22 07:11

laike9m


Starting with Go 1.5, GOMAXPROCS is set to number of CPUs available by default. However, you can explicitly set it using GOMAXPROCS environment variable or by calling runtime.GOMAXPROCS.

https://docs.google.com/document/d/1At2Ls5_fhJQ59kDK2DFVhFu3g5mATSXqqV5QrxinasI/preview?sle=true

like image 11
Khan Avatar answered Nov 13 '22 08:11

Khan