What is the equivalent to ng-if in react.js?

Question

I'm coming to react from using angular and I'm trying to figure out a good react alternative to angular's ng-if directive where I render or dont render an element based on a condition. Take this code for example. I'm using typescript (tsx) btw but that shouldn't matter much.

"use strict";  import * as React from 'react';  interface MyProps {showMe: Boolean} interface MyState {}  class Button extends React.Component <MyProps, MyState>{   constructor(props){     super(props);     this.state = {};   }    render(){     let button;     if (this.props.showMe === true){        button = (         <button type="submit" className="btn nav-btn-red">SIGN UP</button>       )     } else {       button = null;     }     return button;  } } export default Button; 

This solution works, but is there another way that's generally used to achieve this effect? I'm just sort of guessing

Answer 1

How about ternary operator?

render() {   return (     this.props.showMe ? <button type="submit" className="btn nav-btn-red">SIGN UP</button> : null   ); } 

You can also use &&:

render() {   return (     this.props.showMe && <button type="submit" className="btn nav-btn-red">SIGN UP</button>   ); } 

Large block as in the comment can easily be handled by wrapping the JSX in ()s:

render() {   return this.props.showMe && (     <div className="container">       <button type="submit" className="btn nav-btn-red">         SIGN UP       </button>     </div>   ); } 

Also inline:

render() {   return (     <div className="container">       {this.props.showMe && <button type="submit" className="btn nav-btn-red">SIGN UP</button>}     </div>   ); }