What is the difference between type and type.__new__ in python?

Question

I was writing a metaclass and accidentally did it like this:

class MetaCls(type):
    def __new__(cls, name, bases, dict):
        return type(name, bases, dict)

...instead of like this:

class MetaCls(type):
    def __new__(cls, name, bases, dict):
        return type.__new__(cls, name, bases, dict)

What exactly is the difference between these two metaclasses? And more specifically, what caused the first one to not work properly (some classes weren't called into by the metaclass)?

Answer 1

In the first example you're creating a whole new class:

>>> class MetaA(type):
...     def __new__(cls, name, bases, dct):
...         print 'MetaA.__new__'
...         return type(name, bases, dct)
...     def __init__(cls, name, bases, dct):
...         print 'MetaA.__init__'
... 
>>> class A(object):
...     __metaclass__ = MetaA
... 
MetaA.__new__
>>> 

while in the second case you're calling parent's __new__:

>>> class MetaA(type):
...     def __new__(cls, name, bases, dct):
...         print 'MetaA.__new__'
...         return type.__new__(cls, name, bases, dct)
...     def __init__(cls, name, bases, dct):
...         print 'MetaA.__init__'
... 
>>> class A(object):
...     __metaclass__ = MetaA
... 
MetaA.__new__
MetaA.__init__
>>> 

Answer 2

Please refer to the annotation below, hope this helpful.

class MetaCls(type):
    def __new__(cls, name, bases, dict):
        # return a new type named "name",this type has nothing
        # to do with MetaCls,and MetaCl.__init__ won't be invoked
        return type(name, bases, dict)

class MetaCls(type):
    def __new__(cls, name, bases, dict):
        # return a new type named "name",the returned type 
        # is an instance of cls,and cls here is "MetaCls", so 
        # the next step can invoke MetaCls.__init__ 
        return type.__new__(cls, name, bases, dict)