The reinterpret_cast allows the pointer to be treated as an integral type. The result is then bit-shifted and XORed with itself to produce a unique index (unique to a high degree of probability). The index is then truncated by a standard C-style cast to the return type of the function.
reinterpret_cast is a type of casting operator used in C++. It is used to convert a pointer of some data type into a pointer of another data type, even if the data types before and after conversion are different. It does not check if the pointer type and data pointed by the pointer is same or not.
the result of a pointer-to-pointer reinterpret_cast operation can't safely be used for anything other than being cast back to the original pointer type.
No. It is a purely compile-time construct. It is very dangerous, because it lets you get away with very wrong conversions.
int *foo;
float *bar;
// c++ style:
foo = reinterpret_cast< int * >(bar);
// c style:
foo = (int *)(bar);
If you can take the address of the value, one way is to cast a pointer to it to a pointer to a different type, and then dereference the pointer.
For example, an float-to-int conversion:
int main()
{
float f = 1.0f;
printf ("f is %f\n", f);
printf ("(int) f is %d\n", (int)f);
printf ("f as an unsigned int:%x\n", *(unsigned int *)&f);
}
Output:
f is 1.000000
(int) f is 1
f as an unsigned int:3f800000
Note that this is probably not guaranteed to work by the C standard. You cannot use reinterpret_cast to cast from float to int anyway, but it would be similar for a type that was supported (for example, between different pointer types).
Let's confirm the output above makes sense, anyway.
http://en.wikipedia.org/wiki/Single_precision_floating-point_format#IEEE_754_single-precision_binary_floating-point_format:_binary32
The last answer in binary:
0011 1111 1000 0000 0000 0000 0000 0000
This is IEEE-754 floating point format: a sign bit of 0, followed by an 8-bit exponent (011 1111 1), followed by a 23 bit mantissa (all zeroes).
To interpret the exponent, subtract 127: 01111111b = 127, and 127 - 127 = 0. The exponent is 0.
To interpret the mantissa, write it after 1 followed by a decimal point: 1.00000000000000000000000 (23 zeroes). This is 1 in decimal.
Hence the value represented by hex 3f800000 is 1 * 2^0 = 1, as we expected.
C-style casts just look like type names in parenthesis:
void *p = NULL;
int i = (int)p; // now i is most likely 0
Obviously there are better uses for casts than this, but that's the basic syntax.
It doesn't exist, because reinterpret_cast
can not change [constness][3]. For example,
int main()
{
const unsigned int d = 5;
int *g=reinterpret_cast< int* >( &d );
(void)g;
}
will produce the error:
dk.cpp: In function 'int main()':
dk.cpp:5:41: error: reinterpret_cast from type 'const unsigned int*' to type 'int*' casts away qualifiers
A C-style cast is:
int* two = ...;
pointerToOne* one = (pointerToOne*)two;
What about a REINTERPRET
operator for c:
#define REINTERPRET(new_type, var) ( * ( (new_type *) & var ) )
I don't like to say "reinterpret_cast", because cast means conversion (in c), while reinterpret means the opposite: no conversion.
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